Problem of the Week

Updated at Sep 25, 2023 1:54 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of t2+t{t}^{2}+\sqrt{t}?

Check out the solution below!



ddtt2+t\frac{d}{dt} {t}^{2}+\sqrt{t}

1
Use Power Rule: ddxxn=nxn−1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
2t+12t2t+\frac{1}{2\sqrt{t}}

Done
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