Problem of the Week

Updated at Mar 1, 2021 9:57 AM

How can we solve the equation 3(3−p)3−p2=0\frac{3(3-p)}{3-{p}^{2}}=0?

Below is the solution.



3(3−p)3−p2=0\frac{3(3-p)}{3-{p}^{2}}=0

1
Multiply both sides by 3−p23-{p}^{2}.
3(3−p)=03(3-p)=0

2
Divide both sides by 33.
3−p=03-p=0

3
Subtract 33 from both sides.
−p=−3-p=-3

4
Multiply both sides by −1-1.
p=3p=3

Done
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