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\[y=mx+b\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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y=mx+b:b
y=mx+b
y=mx+b
Solving for b. Want to
solve for m
or
solve for x
instead?
1
Subtract
m
x
mx
m
x
from both sides.
y
−
m
x
=
b
y-mx=b
y
−
m
x
=
b
2
Switch sides.
b
=
y
−
m
x
b=y-mx
b
=
y
−
m
x
Done
b=y-m*x
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