${x}^{2}-6x-10=0$

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Quadratic Formula

Complete the Square

Use the Quadratic Formula.

In general, given

a{x}^{2}+bx+c=0

, there exists two solutions where:

x=\frac{-b+\sqrt{{b}^{2}-4ac}}{2a},\frac{-b-\sqrt{{b}^{2}-4ac}}{2a}

In this case,

a=1

b=-6

and

c=-10

{x}^{}=\frac{6+\sqrt{{(-6)}^{2}-4\times -10}}{2},\frac{6-\sqrt{{(-6)}^{2}-4\times -10}}{2}

Simplify.

x=\frac{6+2\sqrt{19}}{2},\frac{6-2\sqrt{19}}{2}

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x=\frac{6+2\sqrt{19}}{2},\frac{6-2\sqrt{19}}{2}

Simplify solutions.

x=3+\sqrt{19},3-\sqrt{19}

Done

Decimal Form: 7.358899, -1.358899

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x2−6x−10=0{x}^{2}-6x-10=0x2−6x−10=0