\[\sqrt{3}{x}^{2}+\sqrt{5}x=12\]

1
Move all terms to one side.
3x2+5x12=0\sqrt{3}{x}^{2}+\sqrt{5}x-12=0

2
Use the Quadratic Formula.
x=5+5+48323,55+48323x=\frac{-\sqrt{5}+\sqrt{5+48\sqrt{3}}}{2\sqrt{3}},\frac{-\sqrt{5}-\sqrt{5+48\sqrt{3}}}{2\sqrt{3}}

Done

Decimal Form: 2.064645, -3.355639

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