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\[\frac{8x+22}{{x}^{2}+4x-5}\]
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"(x+1)/2+4=7"
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pf((8x+22)/(x^2+4x-5))
partial fraction (8x+22)/(x^2+4x-5)
\frac{8x+22}{{x}^{2}+4x-5}
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