\[\int x\sqrt[5]{x-1} \, dx\]

1
Use Power Substitution.
Let u=x15u=\sqrt[5]{x-1}, x=u5+1x={u}^{5}+1, and dx=5u4dudx=5{u}^{4} \, du

2
Substitute variables from above.
(u5+1)u×5u4du\int ({u}^{5}+1)u\times 5{u}^{4} \, du

3
Use Constant Factor Rule: cf(x)dx=cf(x)dx\int cf(x) \, dx=c\int f(x) \, dx.
5u5(u5+1)du5\int {u}^{5}({u}^{5}+1) \, du

4
Expand.
5u10+u5du5\int {u}^{10}+{u}^{5} \, du

5
Use Power Rule: xndx=xn+1n+1+C\int {x}^{n} \, dx=\frac{{x}^{n+1}}{n+1}+C.
5(u1111+u66)5(\frac{{u}^{11}}{11}+\frac{{u}^{6}}{6})

6
Expand.
5(u1111+u66)5(\frac{{u}^{11}}{11}+\frac{{u}^{6}}{6})

7
Substitute u=x15u=\sqrt[5]{x-1} back into the original integral.
5(x15)1111+5(x15)66\frac{5{(\sqrt[5]{x-1})}^{11}}{11}+\frac{5{(\sqrt[5]{x-1})}^{6}}{6}

8
Add constant.
5(x1)11511+5(x1)656+C\frac{5{(x-1)}^{\frac{11}{5}}}{11}+\frac{5{(x-1)}^{\frac{6}{5}}}{6}+C

Done

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