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\[\frac{d}{dx} {x}^{3}+\sec{({x}^{4})}\]
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"(x+1)/2+4=7"
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dif(x^3+sec(x^4))
differentiate x^3+sec(x^4)
\frac{d}{dx} {x}^{3}+\sec{({x}^{4})}
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