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\[9{x}^{2}-1\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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factor(9x^2-1)
factor 9x^2-1
{9x}^{2}-1
1
Rewrite it in the form
a
2
−
b
2
{a}^{2}-{b}^{2}
a
2
−
b
2
, where
a
=
3
x
a=3x
a
=
3
x
and
b
=
1
b=1
b
=
1
.
(
3
x
)
2
−
1
2
{(3x)}^{2}-{1}^{2}
(
3
x
)
2
−
1
2
2
Use
Difference of Squares
:
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
{a}^{2}-{b}^{2}=(a+b)(a-b)
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
.
(
3
x
+
1
)
(
3
x
−
1
)
(3x+1)(3x-1)
(
3
x
+
1
)
(
3
x
−
1
)
Done
(3*x+1)*(3*x-1)
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