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\[9\div 25\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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9#25
9#25
9\div 25
1
Use the algorithm method.
0
.
3
6
2
5
|
9
.
7
.
5
1
.
5
0
1
.
5
0
2
Therefore,
9
÷
25
=
0.36
9\div 25=0.36
9
÷
2
5
=
0
.
3
6
.
0.36
0.36
0
.
3
6
Done
0.36
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