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\[63\div 9\]
+
−
.
ln
>
<
×
÷
/
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≥
≤
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x
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63#9
63#9
63\div 9
1
We can divide
63
63
6
3
items evenly into
7
7
7
groups of
9
9
9
.
2
Therefore,
63
÷
9
=
7
63\div 9=7
6
3
÷
9
=
7
.
7
7
7
Done
7
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