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\[6\div 40\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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6#40
6#40
6\div 40
1
Use the algorithm method.
0
.
1
5
4
0
|
6
.
4
.
0
2
.
0
0
2
.
0
0
2
Therefore,
6
÷
40
=
0.15
6\div 40=0.15
6
÷
4
0
=
0
.
1
5
.
0.15
0.15
0
.
1
5
Done
0.15
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