\[4{x}^{2}-28xy+49{y}^{2}\]

1
Rewrite it in the form a22ab+b2{a}^{2}-2ab+{b}^{2}, where a=2xa=2x and b=7yb=7y.
(2x)22(2x)(7y)+(7y)2{(2x)}^{2}-2(2x)(7y)+{(7y)}^{2}

2
Use Square of Difference: (ab)2=a22ab+b2{(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.
(2x7y)2{(2x-7y)}^{2}

Done

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