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\[48\div 60\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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48#60
48#60
48\div 60
1
Use the algorithm method.
.
8
6
0
|
4
8
.
4
8
.
0
2
Therefore,
48
÷
60
=
0.8
48\div 60=0.8
4
8
÷
6
0
=
0
.
8
.
0.8
0.8
0
.
8
Done
0.8
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