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\[32\div 80\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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32#80
32#80
32\div 80
1
Use the algorithm method.
.
4
8
0
|
3
2
.
3
2
.
0
2
Therefore,
32
÷
80
=
0.4
32\div 80=0.4
3
2
÷
8
0
=
0
.
4
.
0.4
0.4
0
.
4
Done
0.4
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