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27
÷
9
27\div 9
2
7
÷
9
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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27#9
27#9
27\div 9
1
We can divide
27
27
2
7
items evenly into
3
3
3
groups of
9
9
9
.
2
Therefore,
27
÷
9
=
3
27\div 9=3
2
7
÷
9
=
3
.
3
3
3
Done
3
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