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25
0.5
{25}^{0.5}
2
5
0
.
5
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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25^0.5
25^0.5
{25}^{0.5}
1
Rewrite
25
25
2
5
as
5
2
{5}^{2}
5
2
.
(
5
2
)
0.5
{({5}^{2})}^{0.5}
(
5
2
)
0
.
5
2
Use this rule:
(
x
a
)
b
=
x
a
b
{({x}^{a})}^{b}={x}^{ab}
(
x
a
)
b
=
x
a
b
.
5
5
5
Done
5
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