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\[12\div 792\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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12#792
12#792
12\div 792
1
Use the algorithm method.
.
1
5
1
5
1
7
9
2
|
1
2
.
7
.
9
2
4
.
0
8
0
3
.
9
6
0
1
2
0
0
7
9
2
4
0
8
0
3
9
6
0
1
2
0
0
7
9
2
4
0
8
2
Therefore,
12
÷
792
≈
0.015151
12\div 792\approx0.015151
1
2
÷
7
9
2
≈
0
.
0
1
5
1
5
1
.
0.015152
0.015152
0
.
0
1
5
1
5
2
Done
0.015151515151515
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