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115
÷
23
115\div 23
1
1
5
÷
2
3
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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115#23
115#23
115\div 23
Available Methods
Algorithm
Partial Quotient
Box
1
Use the algorithm method.
5
2
3
|
1
1
5
1
1
5
2
Therefore,
115
÷
23
=
5
115\div 23=5
1
1
5
÷
2
3
=
5
.
5
5
5
Done
5
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