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\[1125\div 3\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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1125#3
1125#3
1125\div 3
Available Methods
Algorithm
Partial Quotient
Box
1
Use the algorithm method.
3
7
5
3
|
1
1
2
5
9
2
2
2
1
1
5
1
5
2
Therefore,
1125
÷
3
=
375
1125\div 3=375
1
1
2
5
÷
3
=
3
7
5
.
375
375
3
7
5
Done
375
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