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\[1.8\div 5\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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1.8#5
1.8#5
1.8\div 5
1
Use the algorithm method.
0
.
3
6
5
|
1
.
8
1
.
5
3
0
3
0
2
Therefore,
1.8
÷
5
=
0.36
1.8\div 5=0.36
1
.
8
÷
5
=
0
.
3
6
.
0.36
0.36
0
.
3
6
Done
0.36
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