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\[(x-9)(x+9)\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
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)
log
x
=
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expand((x-9)(x+9))
expand (x-9)(x+9)
(x-9)(x+9)
1
Use
Difference of Squares
:
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
{a}^{2}-{b}^{2}=(a+b)(a-b)
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
.
x
2
−
9
2
{x}^{2}-{9}^{2}
x
2
−
9
2
2
Simplify
9
2
{9}^{2}
9
2
to
81
81
8
1
.
x
2
−
81
{x}^{2}-81
x
2
−
8
1
Done
x^2-81
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