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\[{(x-3)}^{2}\]
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
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expand((x-3)^2)
expand (x-3)^2
{(x-3)}^{2}
1
Use
Square of Difference
:
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
{(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
.
x
2
−
2
x
×
3
+
3
2
{x}^{2}-2x\times 3+{3}^{2}
x
2
−
2
x
×
3
+
3
2
2
Simplify
3
2
{3}^{2}
3
2
to
9
9
9
.
x
2
−
2
x
×
3
+
9
{x}^{2}-2x\times 3+9
x
2
−
2
x
×
3
+
9
3
Simplify
2
x
×
3
2x\times 3
2
x
×
3
to
6
x
6x
6
x
.
x
2
−
6
x
+
9
{x}^{2}-6x+9
x
2
−
6
x
+
9
Done
x^2-6*x+9
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