\[(2x-3y+z)(2x+3y-z)\]

1
Expand by distributing sum groups.
2x(2x+3yz)3y(2x+3yz)+z(2x+3yz)2x(2x+3y-z)-3y(2x+3y-z)+z(2x+3y-z)

2
Expand by distributing terms.
4x2+6xy2xz3y(2x+3yz)+z(2x+3yz)4{x}^{2}+6xy-2xz-3y(2x+3y-z)+z(2x+3y-z)

3
Expand by distributing terms.
4x2+6xy2xz(6yx+9y23yz)+z(2x+3yz)4{x}^{2}+6xy-2xz-(6yx+9{y}^{2}-3yz)+z(2x+3y-z)

4
Expand by distributing terms.
4x2+6xy2xz(6yx+9y23yz)+2zx+3zyz24{x}^{2}+6xy-2xz-(6yx+9{y}^{2}-3yz)+2zx+3zy-{z}^{2}

5
Remove parentheses.
4x2+6xy2xz6yx9y2+3yz+2zx+3zyz24{x}^{2}+6xy-2xz-6yx-9{y}^{2}+3yz+2zx+3zy-{z}^{2}

6
Collect like terms.
4x2+(6xy6xy)+(2xz+2xz)9y2+(3yz+3yz)z24{x}^{2}+(6xy-6xy)+(-2xz+2xz)-9{y}^{2}+(3yz+3yz)-{z}^{2}

7
Simplify.
4x29y2+6yzz24{x}^{2}-9{y}^{2}+6yz-{z}^{2}

Done

How can we make this solution more helpful?