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x
2
−
x
=
12
{x}^{2}-x=12
x
2
−
x
=
1
2
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
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x^2-x=12
x^2-x=12
{x}^{2}-x=12
1
Move all terms to one side.
x
2
−
x
−
12
=
0
{x}^{2}-x-12=0
x
2
−
x
−
1
2
=
0
2
Factor
x
2
−
x
−
12
{x}^{2}-x-12
x
2
−
x
−
1
2
.
1
Ask: Which two numbers add up to
−
1
-1
−
1
and multiply to
−
12
-12
−
1
2
?
−
4
-4
−
4
and
3
3
3
2
Rewrite the expression using the above.
(
x
−
4
)
(
x
+
3
)
(x-4)(x+3)
(
x
−
4
)
(
x
+
3
)
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!
(
x
−
4
)
(
x
+
3
)
=
0
(x-4)(x+3)=0
(
x
−
4
)
(
x
+
3
)
=
0
3
Solve for
x
x
x
.
1
Ask: When will
(
x
−
4
)
(
x
+
3
)
(x-4)(x+3)
(
x
−
4
)
(
x
+
3
)
equal zero?
When
x
−
4
=
0
x-4=0
x
−
4
=
0
or
x
+
3
=
0
x+3=0
x
+
3
=
0
2
Solve each of the 2 equations above.
x
=
4
,
−
3
x=4,-3
x
=
4
,
−
3
To get access to all 'How?' and 'Why?' steps, join
Cymath Plus
!
x
=
4
,
−
3
x=4,-3
x
=
4
,
−
3
Done
x=4,-3
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