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\[9-3\div \frac{1}{3}+1\]
+
−
.
ln
>
<
×
÷
/
log
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≤
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)
log
x
=
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9-3#1/3+1
9-3#1/3+1
9-3\div \frac{1}{3}+1
1
Use this rule:
a
÷
b
c
=
a
×
c
b
a\div \frac{b}{c}=a\times \frac{c}{b}
a
÷
c
b
=
a
×
b
c
.
9
−
3
×
3
+
1
9-3\times 3+1
9
−
3
×
3
+
1
2
Simplify
3
×
3
3\times 3
3
×
3
to
9
9
9
.
9
−
9
+
1
9-9+1
9
−
9
+
1
3
Simplify
9
−
9
9-9
9
−
9
to
0
0
0
.
0
+
1
0+1
0
+
1
4
Simplify.
1
1
1
Done
1
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